Integrand size = 20, antiderivative size = 45 \[ \int \frac {(1-2 x)^3 (2+3 x)}{(3+5 x)^3} \, dx=\frac {316 x}{625}-\frac {12 x^2}{125}-\frac {1331}{6250 (3+5 x)^2}-\frac {3267}{3125 (3+5 x)}-\frac {2046 \log (3+5 x)}{3125} \]
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Time = 0.02 (sec) , antiderivative size = 45, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 1, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.050, Rules used = {78} \[ \int \frac {(1-2 x)^3 (2+3 x)}{(3+5 x)^3} \, dx=-\frac {12 x^2}{125}+\frac {316 x}{625}-\frac {3267}{3125 (5 x+3)}-\frac {1331}{6250 (5 x+3)^2}-\frac {2046 \log (5 x+3)}{3125} \]
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Rule 78
Rubi steps \begin{align*} \text {integral}& = \int \left (\frac {316}{625}-\frac {24 x}{125}+\frac {1331}{625 (3+5 x)^3}+\frac {3267}{625 (3+5 x)^2}-\frac {2046}{625 (3+5 x)}\right ) \, dx \\ & = \frac {316 x}{625}-\frac {12 x^2}{125}-\frac {1331}{6250 (3+5 x)^2}-\frac {3267}{3125 (3+5 x)}-\frac {2046 \log (3+5 x)}{3125} \\ \end{align*}
Time = 0.02 (sec) , antiderivative size = 46, normalized size of antiderivative = 1.02 \[ \int \frac {(1-2 x)^3 (2+3 x)}{(3+5 x)^3} \, dx=-\frac {33803+47130 x-53650 x^2-61000 x^3+15000 x^4+4092 (3+5 x)^2 \log (6+10 x)}{6250 (3+5 x)^2} \]
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Time = 2.47 (sec) , antiderivative size = 32, normalized size of antiderivative = 0.71
method | result | size |
risch | \(-\frac {12 x^{2}}{125}+\frac {316 x}{625}+\frac {-\frac {3267 x}{625}-\frac {20933}{6250}}{\left (3+5 x \right )^{2}}-\frac {2046 \ln \left (3+5 x \right )}{3125}\) | \(32\) |
default | \(\frac {316 x}{625}-\frac {12 x^{2}}{125}-\frac {1331}{6250 \left (3+5 x \right )^{2}}-\frac {3267}{3125 \left (3+5 x \right )}-\frac {2046 \ln \left (3+5 x \right )}{3125}\) | \(36\) |
norman | \(\frac {\frac {19664}{1875} x +\frac {53117}{2250} x^{2}+\frac {244}{25} x^{3}-\frac {12}{5} x^{4}}{\left (3+5 x \right )^{2}}-\frac {2046 \ln \left (3+5 x \right )}{3125}\) | \(37\) |
parallelrisch | \(-\frac {135000 x^{4}+920700 \ln \left (x +\frac {3}{5}\right ) x^{2}-549000 x^{3}+1104840 \ln \left (x +\frac {3}{5}\right ) x -1327925 x^{2}+331452 \ln \left (x +\frac {3}{5}\right )-589920 x}{56250 \left (3+5 x \right )^{2}}\) | \(51\) |
meijerg | \(\frac {x \left (\frac {5 x}{3}+2\right )}{27 \left (1+\frac {5 x}{3}\right )^{2}}-\frac {x^{2}}{6 \left (1+\frac {5 x}{3}\right )^{2}}-\frac {x \left (15 x +6\right )}{75 \left (1+\frac {5 x}{3}\right )^{2}}-\frac {2046 \ln \left (1+\frac {5 x}{3}\right )}{3125}+\frac {x \left (\frac {100}{9} x^{2}+30 x +12\right )}{25 \left (1+\frac {5 x}{3}\right )^{2}}+\frac {36 x \left (-\frac {625}{27} x^{3}+\frac {500}{9} x^{2}+150 x +60\right )}{3125 \left (1+\frac {5 x}{3}\right )^{2}}\) | \(97\) |
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Time = 0.21 (sec) , antiderivative size = 52, normalized size of antiderivative = 1.16 \[ \int \frac {(1-2 x)^3 (2+3 x)}{(3+5 x)^3} \, dx=-\frac {15000 \, x^{4} - 61000 \, x^{3} - 89400 \, x^{2} + 4092 \, {\left (25 \, x^{2} + 30 \, x + 9\right )} \log \left (5 \, x + 3\right ) + 4230 \, x + 20933}{6250 \, {\left (25 \, x^{2} + 30 \, x + 9\right )}} \]
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Time = 0.05 (sec) , antiderivative size = 36, normalized size of antiderivative = 0.80 \[ \int \frac {(1-2 x)^3 (2+3 x)}{(3+5 x)^3} \, dx=- \frac {12 x^{2}}{125} + \frac {316 x}{625} - \frac {32670 x + 20933}{156250 x^{2} + 187500 x + 56250} - \frac {2046 \log {\left (5 x + 3 \right )}}{3125} \]
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Time = 0.24 (sec) , antiderivative size = 36, normalized size of antiderivative = 0.80 \[ \int \frac {(1-2 x)^3 (2+3 x)}{(3+5 x)^3} \, dx=-\frac {12}{125} \, x^{2} + \frac {316}{625} \, x - \frac {121 \, {\left (270 \, x + 173\right )}}{6250 \, {\left (25 \, x^{2} + 30 \, x + 9\right )}} - \frac {2046}{3125} \, \log \left (5 \, x + 3\right ) \]
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Time = 0.29 (sec) , antiderivative size = 32, normalized size of antiderivative = 0.71 \[ \int \frac {(1-2 x)^3 (2+3 x)}{(3+5 x)^3} \, dx=-\frac {12}{125} \, x^{2} + \frac {316}{625} \, x - \frac {121 \, {\left (270 \, x + 173\right )}}{6250 \, {\left (5 \, x + 3\right )}^{2}} - \frac {2046}{3125} \, \log \left ({\left | 5 \, x + 3 \right |}\right ) \]
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Time = 0.04 (sec) , antiderivative size = 32, normalized size of antiderivative = 0.71 \[ \int \frac {(1-2 x)^3 (2+3 x)}{(3+5 x)^3} \, dx=\frac {316\,x}{625}-\frac {2046\,\ln \left (x+\frac {3}{5}\right )}{3125}-\frac {\frac {3267\,x}{15625}+\frac {20933}{156250}}{x^2+\frac {6\,x}{5}+\frac {9}{25}}-\frac {12\,x^2}{125} \]
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